a.bat内容如下:
@echo off
CALL :AA 01 03 05
goto :END
:AA
For /L %%s IN (1,1,3) DO (
echo cc.c%1
shift /1
)
goto :eof
:END
echo OK!!!
运行结果:
cc.c01
cc.c01
cc.c01
OK!!!
请问如何得到
cc.c01
cc.c02
cc.c03
OK!!!
[ Last edited by blancy on 2009-2-25 at 10:53 ]
@echo off
CALL :AA 01 03 05
goto :END
:AA
For /L %%s IN (1,1,3) DO (
echo cc.c%1
shift /1
)
goto :eof
:END
echo OK!!!
运行结果:
cc.c01
cc.c01
cc.c01
OK!!!
请问如何得到
cc.c01
cc.c02
cc.c03
OK!!!
[ Last edited by blancy on 2009-2-25 at 10:53 ]
新手上路,请多关照
