在执行一个脚本时,脚本内容如下:
@echo on
set REPOS=%1
set REV=%2
set RD=%RANDOM%
svnlook info %REPOS% > D:\TempFIle\INFO_%RD%.txt
svnlook changed %REPOS% > D:\TempFIle\CHG_%RD%.txt
sed -e "1p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set user=%%i
sed -e "2p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set dtime=%%i
sed -e "4p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set LOG_MSG=%%i
echo Dear %user% : >> D:\TempFIle\MSG_%RD%.txt
echo The Current Version After Commit :%REV% >> D:\TempFIle\MSG_%RD%.txt
echo Commit time :%dtime% >> D:\TempFIle\MSG_%RD%.txt
echo Commit LOg :%LOG_MSG% >> D:\TempFIle\MSG_%RD%.txt
echo The Commit COntent : >> D:\TempFIle\MSG_%RD%.txt
echo. >> D:\TempFIle\MSG_%RD%.txt
type D:\TempFIle\CHG_%RD%.txt >> D:\TempFIle\MSG_%RD%.txt
type D:\TempFIle\scm.txt >> D:\TempFIle\MSG_%RD%.txt
blat D:\TempFIle\MSG_%RD%.txt -to %user%@*.*.com -base64 -charset Gb2312 -subject "Subversion_Notes Commit~User:%user% Version:%REV%" -server smtp.*.*.com -u scm -pw ****** -f scm@corp.**.com
exit 0
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在执行下面三行时,始终提示不应有%%i,这是什么原因呢?由于是用的别人的脚本,对这三行的意思只是有个大概的理解,请问%%i在这里是什么意思呢?多谢各位了。
sed -e "1p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set user=%%i
sed -e "2p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set dtime=%%i
sed -e "4p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set LOG_MSG=%%i
@echo on
set REPOS=%1
set REV=%2
set RD=%RANDOM%
svnlook info %REPOS% > D:\TempFIle\INFO_%RD%.txt
svnlook changed %REPOS% > D:\TempFIle\CHG_%RD%.txt
sed -e "1p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set user=%%i
sed -e "2p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set dtime=%%i
sed -e "4p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set LOG_MSG=%%i
echo Dear %user% : >> D:\TempFIle\MSG_%RD%.txt
echo The Current Version After Commit :%REV% >> D:\TempFIle\MSG_%RD%.txt
echo Commit time :%dtime% >> D:\TempFIle\MSG_%RD%.txt
echo Commit LOg :%LOG_MSG% >> D:\TempFIle\MSG_%RD%.txt
echo The Commit COntent : >> D:\TempFIle\MSG_%RD%.txt
echo. >> D:\TempFIle\MSG_%RD%.txt
type D:\TempFIle\CHG_%RD%.txt >> D:\TempFIle\MSG_%RD%.txt
type D:\TempFIle\scm.txt >> D:\TempFIle\MSG_%RD%.txt
blat D:\TempFIle\MSG_%RD%.txt -to %user%@*.*.com -base64 -charset Gb2312 -subject "Subversion_Notes Commit~User:%user% Version:%REV%" -server smtp.*.*.com -u scm -pw ****** -f scm@corp.**.com
exit 0
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在执行下面三行时,始终提示不应有%%i,这是什么原因呢?由于是用的别人的脚本,对这三行的意思只是有个大概的理解,请问%%i在这里是什么意思呢?多谢各位了。
sed -e "1p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set user=%%i
sed -e "2p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set dtime=%%i
sed -e "4p" -n D:\TempFIle\INFO_%RD%.txt > D:\TempFIle\temp.txt&&for /f %%i in (D:\TempFIle\temp.txt) do set LOG_MSG=%%i

