中国DOS联盟

The old-fashioned person thinks too much. Only the problem-solving code for specific issues needs to consider many issues in the application, such as exception handling, interface optimization, default values, and so on. But what we are discussing now is just some prototypical code, which can't be talked about how to apply it at all. We just need to abstract the core of the problem and then solve it.

@echo off&setlocal enabledelayedexpansion

set/p p=请输入:

set str=27j834fi56a901bghcde

set st=!str!&set pt=!p!

:lp

set ..!p:~%n%,1!=ok&set/a n+=1

set .!str:~,1!=!str:~-1,1!

set str=!str:~1,-1!

if defined str goto lp

:lp1

if defined ..%st:~,1% (set var1=!var1!%st:~,1%&set var2=!.%st:~,1%!!var2!)else (

if defined ..!.%st:~,1%! (set var1=!var1!%st:~,1%&set var2=!.%st:~,1%!!var2!)else set var1=!var1!#&set var2=#!var2!)

set st=!st:~1,-1!&set pt=!pt:~1!

if defined st goto lp1

echo !var1! ^| !var2!

pause

No need to enter spaces

@echo off&setlocal enabledelayedexpansion

set/p p=Please enter:

set str=27j834fi56a901bghcde

set st=!str!&set pt=!p!

:lp

set ..!p:~%n%,1!=ok&set/a n+=1

set .!str:~,1!=!str:~-1,1!

set str=!str:~1,-1!

if defined str goto lp

:lp1

if defined ..%st:~,1% (set var1=!var1!%st:~,1%&set var2=!.%st:~,1!%%var2!)else (

if defined ..!.%st:~,1%! (set var1=!var1!%st:~,1%&set var2=!.%st:~,1!%%var2!)else set var1=!var1!#&set var2=#!var2!)

set st=!st:~1,-1!&set pt=!pt:~1!

if defined st goto lp1

echo !var1! ^| !var2!

pause

This is correct.
Brother, this if defined ..!.%st:~,1%! is really amazing, I've learned it.

Still need to pick some flaws.

I don't understand the others, just this line set str=27j834fi56a901bghcde

It still doesn't seem very universal.

Comrades, please forgive me, my level is not good, I can only pick flaws.

Originally posted by quya at 2008-7-13 09:53:
Still need to pick some flaws.

I can't understand the others, just this line set str=27j834fi56a901bghcde

It still seems not very universal.

Comrades, please forgive me, my level is not good, I can only pick flaws.

Old-fashioned, this set is based on the situation. For example, if it is to be symmetrical with numbers and letters, then set str=numbers+letters. If it is to be symmetrical with numbers and Chinese characters, then set str=numbers+Chinese characters. If the symmetrical relationship is irregular, then it is set as terse brother did.

@echo off

set/p input=请输入:

set "string=012t457689aycd0fghi3"

set num=

:pro1

set /a num+=1

set strtmp=%string:~0,1%%string:~-1%

set str%num%=##

rem 下面这句是 findstr  类方面的应用

echo %input%|findstr >nul&&set str%num%=%strtmp%

set string=%string:~1,-1%

if not defined string goto pro2

goto pro1



:pro2

setlocal enabledelayedexpansion

set str_1=x

for /l %%i in (1,1,%num%) do call set str_1=!str_1:~0,-1!%%str%%i%%

for /l %%i in (1,1,%num%) do call set str_2=%%str%%i%%!str_2:~1!

echo %str_1:~,-1% ^| %str_2:~1,-2%



pause

Originally posted by zw19750516 at 2008-7-13 10:14 AM:

Old-fashioned, this set is based on the situation. For example, if you want to be symmetrical with numbers and letters, then set str=numbers+letters. If you want to be symmetrical with numbers and Chinese characters, then set str=numbers+Chinese characters. If the symmetrical relationship is irregular, then set it as terse brother did.

My understanding of your question is that symmetry has nothing to do with numbers and letters.

As long as you find the input value, it will be displayed at that position, and then displayed at the symmetrical position of that position. Both numbers and letters can be in random order.

So I am very confused about your problem-solving ideas.

For example, the following is random and repeated, (there are 2 zeros), it can also be displayed correctly.

But I currently can't solve the problem of spaces in the original characters. Spaces can be entered.

@echo off

set/p input=Please enter:

set "string=012t457689aycd0fghi3"

set num=

:pro1

set /a num+=1

set strtmp=%string:~0,1%%string:~-1%

set str%num%=##

rem The following sentence is an application of findstr  class

echo %input%|findstr >nul&&set str%num%=%strtmp%

set string=%string:~1,-1%

if not defined string goto pro2

goto pro1



:pro2

setlocal enabledelayedexpansion

set str_1=x

for /l %%i in (1,1,%num%) do call set str_1=!str_1:~0,-1!%%str%%i%%

for /l %%i in (1,1,%num%) do call set str_2=%%str%%i%%!str_2:~1!

echo %str_1:~,-1% ^| %str_2:~1,-2%



pause

Last edited by quya on 2008-7-13 at 10:35 AM ]

@echo off

set code=0123456789abcdefghijklmnopqrstuvwxyz&set n=36

:again

set /a a=%random%%%n%

call,set a=%%code:~%a%,1%%

call,set code=%%code:%a%=%%

set str=%str%%a%&set /a n-=1

if %n% neq 16 goto again

echo %str%&pause>nul

It can be out of order. You can even generate it through code, such as:

@echo off

set code=0123456789abcdefghijklmnopqrstuvwxyz&set n=36

:again

set /a a=%random%%%n%

call,set a=%%code:~%a%,1%%

call,set code=%%code:%a%=%%

set str=%str%%a%&set /a n-=1

if %n% neq 16 goto again

echo %str%&pause>nul

Then the original poster uses your scrambling to re-examine all the solutions.

The program can only modify the line "set code=arbitrary characters". The meaning of arbitrary characters is that what was originally given, just write that.

Last edited by quya on 2008-7-13 at 10:58 AM ]

Hehe, the old-fashioned person is really persistent,
You can try the code on floor 38. It has handled human-computer interaction, and you can input without spaces or with spaces.
The shortcoming is: there should be no duplicates in any characters.

Originally posted by 26933062 at 2008-7-13 11:13 AM:
Hehe, Laotu is really persistent,
You can try the code on floor 38,
It has handled human-computer interaction, you can not enter spaces or can enter.
The shortcoming is: There should be no duplicates in any characters.

Tried when set "str=012t456789abcd6fghi3"

Entering 36 cannot display correctly.

But my code on floor 37 is completely accurate, finally won over the masters.

Just feel that I'm not too stupid, no other meaning.

Last edited by quya on 2008-7-13 at 11:34 AM ]

Originally posted by quya at 2008-7-13 11:32:


Tried it. When set "str=012t456789abcd6fghi3"

Entering 36 does not display correctly.

And my code on floor 37 is completely accurate, finally winning over the experts.

Just feel that I'm not too stupid...

It's already said that there can't be duplicates. There are two 6s here?

@echo off

set/p input=请输入:

set string=0123456789abcdefghij

set "str= "



:loop

set str=%string:~-1%%str%%string:~0,1%

echo %input%|findstr >nul||set str=#%str:~1,-1%%#

set string=%string:~1,-1%

if not defined string goto end

goto loop



:end

for /f "tokens=1,2 delims= " %%i in ("%str%") do echo %%j ^| %%i

pause

setlocal EnableDelayedExpansion

set string=0123456789abcdefghij

for /l %%i in (1,1,10) do (

set string=!string:~1,-1!

echo !string!

if not defined string goto end)

Another idea, this should be the simplest one. Not even using a delay variable.

@echo off

set/p input=Please enter:

set string=0123456789abcdefghij

set "str= "



:loop

set str=%string:~-1%%str%%string:~0,1%

echo %input%|findstr >nul||set str=#%str:~1,-1%%#

set string=%string:~1,-1%

if not defined string goto end

goto loop



:end

for /f "tokens=1,2 delims= " %%i in ("%str%") do echo %%j ^| %%i

pause

Actually I want to use delay variables, but I don't know how to use them. At first I thought of writing like the following.

setlocal EnableDelayedExpansion

set string=0123456789abcdefghij

for /l %%i in (1,1,10) do (

set string=!string:~1,-1!

echo !string!

if not defined string goto end)

My expected result is that the variable String gradually becomes shorter, but the first step is not successful, and then the subsequent ideas are all messed up. I really don't understand why I can't achieve the result, please experts give pointers, thank you!

Last edited by quya on 2008-7-14 at 10:39 AM ]

Old-fashioned. Efficiency is the first consideration in code, and simplicity is the second. Your solution has an efficiency issue, and at the same time ('echo %str%') can be modified to ("%str%").

Is there an efficiency issue with such a simple code in floor 57? Please briefly analyze it, thanks.

%str% has been modified as you suggested, but I still don't understand why. Originally, I just wrote %str%, and the program treated this variable as a file, so I used ECHO. I didn't know I could add "".

Last edited by quya on 2008-7-14 at 10:41 AM ]

The efficiency issue is here: echo %input%|findstr >nul||set str=#%str:~1,-1%%#
In batch processing, try to use if for judgment as much as possible and use findstr less.