中国DOS联盟

@echo off
:cx
tasklist>1.txt
type 1.txt|find "Christmas day.exe">2.txt
set /p c=<2.txt
set a=%c:~0,17%
echo %a%>1.txt
set /p b=<1.txt
if not "%b%"=="Christmas day.exe" goto gb
if "%b%"=="Christmas day.exe" goto cx
:gb
echo 进程不存在
del 1.txt
del 2.txt
pause

我这样来循环判断Christmas day.exe进程时，当先Christmas day.exe，之后，再打开这个文件，然后关闭Christmas day.exe后，发现不会跳转到“进程不存在”这。我要一直检测这个进程，当这个进程退出后就跳转执行另一条命令，该怎么做啊？

@echo off

:loop

tasklist | findstr /i "notepad.exe">nul && call :success || call :failure

pause

goto loop

goto :eof



:success

echo %time%存在!

goto :eof



:failure

echo %time%不存在!

goto :eof

如果进程名中包含空格，则findstr应加上/c参数:tasklist | findstr /ic:"aa aa.exe">nul && call :success || call :failure
更严谨一点应该加上/r和^:
tasklist | findstr /irc:"^aa aa.exe">nul && call :success || call :failure

@echo off

start x:\Christmas day.exe

goto loop1

:loop1

echo 等待Christmas day.exe

ping 127.1 -n 2 >nul

tasklist|find /i "Christmas day.exe">nul && goto loop2 || goto loop1

:loop2

echo 正在运行Christmas day.exe

ping 127.1 -n 2 >nul

tasklist|find /i "Christmas day.exe">nul && goto loop2 || goto end

:end

call xxx.bat

一个简单的循环判断进程的方法...
我自己一直用这个...
技术烂 写不出好代码..

Last edited by zxh17173 on 2009-12-25 at 19:33 ]