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Brother namajm, is the code in F11 a test error code or a correct code?

I tested here and it didn't pass. It shows "ab" instead of the "ab c" we want. I don't know why.

I'm sorry, the example I gave was to show that the code couldn't correctly get the folder name of the specified level in the path with spaces. I didn't make it clear at that time, but now it's commented properly.

The code in 14F is really remarkable. It uses a relatively obscure shift, which is quite skillful. It might be the most general-purpose one.

　　Hehe...

　　I've been thinking about this question all the time:

　　Why does the code on floor 11 not work, but the code on floor 14 does? Is it just the role of this shift? I still don't understand why we need to loop 4 times.

@echo off

setlocal ENABLEDELAYEDEXPANSION

    set str=c:\ab c\def\gh .exe\

    set num=1

    for /l %%i in (1,1,%num%) do set "str=!str:*\=!"

    echo %str:\= && 2>nul cd %

pause

Take a look at <Help and Support> more. Different combinations have different flavors, which is also one of the reasons for the existence of scripts:

@echo off

setlocal ENABLEDELAYEDEXPANSION

    set str=c:\ab c\def\gh .exe\

    set num=1

    for /l %%i in (1,1,%num%) do set "str=!str:*\=!"

    echo %str:\= && 2>nul cd %

pause

Changing the final cd to echo allows displaying level by level. The several methods are used in different situations, and as for which is better or worse, that is a matter of personal opinion.

I found the sentence "echo %str:\= && 2>nul cd %". I can't figure out how to write to remove the last few content separated by \. I hope 3742668 can explain it.

In addition, when extracting the folder name from "echo %str:\= && 2>nul cd %", the last character is a space. There is no this problem when extracting the file name. It can be changed to "echo %str:\=&& 2>nul cd %" (note: there is a space before && in the two statements and no space in one).

Originally posted by 3742668 at 2006-10-21 07:35:
Take a look at the <Help and Support> more.
Different combinations have different flavors, which is also one of the reasons why scripts exist:
Several methods are used in different situations, and as for which is better or worse, that is a matter of personal opinion.

Agree, there are various ways to solve problems, just see how you use them.

set "command=set i=3"

echo i的值:%i% & pause

%command%

echo i的值:%i% & pause

Originally posted by namejm at 2006-10-21 08:39:
　　I found that in the sentence "echo %str:\= && 2>nul cd %", replacing "cd" with any command can execute correctly. I can't figure out the writing method of removing the last few \-separated contents. I still need to ask 37426...

I remember that a similar method was used in that post discussing encryption and decryption.
The principle is very simple, for example:

set "command=set i=3"

echo i的值:%i% & pause

%command%

echo i的值:%i% & pause

Reference: Non-compiled Batch Processing Encryption Scheme and Code of 11F scheme.
In addition, in fact, there is still a small problem with the last method. When getting the final file name, a prompt like "ECHO is on" might be displayed. To save code quantity, it was not processed.

Originally posted by 3742668 at 2006-10-21 09:00:

I remember that a similar method was used in that post discussing encryption and decryption.
The principle is very simple, for example:

set "command=set i=3"

echo i的值:%i% & pause

%command%

ech ... 




After testing, it does appear: "The prompt that ECHO is on/off", I don't know how to solve this problem, I often encounter this problem...

May I ask under what circumstances the prompt "ECHO is in the on/off state" appears? Please send out the test path for me to take a look. It is estimated that changing echo %str:\= && 2>nul cd % to echo. %str:\=&& 2>nul cd % will work (note that there is a dot after echo).

Well, strong! Worth learning~!