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Function getSalt(intLen)
' Function takes a given length x and generates a random hex value of x digits.
' Salt can be used to help protect passwords. When a password is first stored in a
' database generate a salt value also. Concatenate the salt value with the password,
' and then encrypt it using the HashEncode function below. Store both the salt value,
' and the encrypted value in the database. When a password needs to be verified, take
' the password concatenate the salt from the database. Encode it using the HashEncode
' function below. If the result matches the the encrypted password stored in the
' database, then it is a match. If not then the password is invalid.
'
'
' Note: Passwords become case sensitive when using this encryption.
' For more information on Password HASH Encoding, and SALT visit: http://local.15seconds.com/issue/000217.htm
'
' Call this function if you wish to generate a random hex value of any given length
'
' Written By: Mark G. Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
Dim strSalt
Dim intIndex, intRand
If Not IsNumeric(intLen) Then
getSalt = "00000000"
exit function
ElseIf CInt(intLen) <> CDbl(intLen) Or CInt(intLen) < 1 Then
getSalt = "00000000"
exit function
End If
Randomize
For intIndex = 1 to CInt(intLen)
intRand = CInt(Rnd * 1000) Mod 16
strSalt = strSalt & getDecHex(intRand)
Next
getSalt = strSalt
End Function
Function HashEncode(strSecret)
' Function takes an ASCII string less than 2^61 characters long and
' one way hash encrypts it using 160 bit encryption into a 40 digit hex value.
' The encoded hex value cannot be decoded to the original string value.
'
' This is the only function that you need to call for encryption.
'
' Written By: Mark G. Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
' The author makes no warranties as to the validity, and/or authenticity of this code.
' You may use any code found herein at your own risk.
' This code was written to follow as closely as possible the standards found in
' Federal Information Processing Standards Publication (FIPS PUB 180-1)
' http://csrc.nist.gov/fips/fip180-1.txt -- Secure Hash Standard SHA-1
'
' This code is for private use only, and the security and/or encryption of the resulting
' hexadecimal value is not warrented or gaurenteed in any way.
'
Dim strEncode, strH(4)
Dim intPos
If len(strSecret) = 0 or len(strSecret) >= 2^61 then
HashEncode = "0000000000000000000000000000000000000000"
exit function
end if
'Initial Hex words are used for encoding Digest.
'These can be any valid 8-digit hex value (0 to F)
strH(0) = "FB0C14C2"
strH(1) = "9F00AB2E"
strH(2) = "991FFA67"
strH(3) = "76FA2C3F"
strH(4) = "ADE426FA"
For intPos = 1 to len(strSecret) step 56
strEncode = Mid(strSecret, intPos, 56) 'get 56 character chunks
strEncode = WordToBinary(strEncode) 'convert to binary
strEncode = PadBinary(strEncode) 'make it 512 bites
strEncode = BlockToHex(strEncode) 'convert to hex value
'Encode the hex value using the previous runs digest
'If it is the first run then use the initial values above
strEncode = DigestHex(strEncode, strH(0), strH(1), strH(2), strH(3), strH(4))
'Combine the old digest with the new digest
strH(0) = HexAdd(left(strEncode, 8), strH(0))
strH(1) = HexAdd(mid(strEncode, 9, 8), strH(1))
strH(2) = HexAdd(mid(strEncode, 17, 8), strH(2))
strH(3) = HexAdd(mid(strEncode, 25, 8), strH(3))
strH(4) = HexAdd(right(strEncode, 8), strH(4))
Next
'This is the final Hex Digest
HashEncode = strH(0) & strH(1) & strH(2) & strH(3) & strH(4)
End Function
Function HexToBinary(btHex)
' Function Converts a single hex value into it's binary equivalent
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Select Case btHex
Case "0"
HexToBinary = "0000"
Case "1"
HexToBinary = "0001"
Case "2"
HexToBinary = "0010"
Case "3"
HexToBinary = "0011"
Case "4"
HexToBinary = "0100"
Case "5"
HexToBinary = "0101"
Case "6"
HexToBinary = "0110"
Case "7"
HexToBinary = "0111"
Case "8"
HexToBinary = "1000"
Case "9"
HexToBinary = "1001"
Case "A"
HexToBinary = "1010"
Case "B"
HexToBinary = "1011"
Case "C"
HexToBinary = "1100"
Case "D"
HexToBinary = "1101"
Case "E"
HexToBinary = "1110"
Case "F"
HexToBinary = "1111"
Case Else
HexToBinary = "2222"
End Select
End Function
Function BinaryToHex(strBinary)
' Function Converts a 4 bit binary value into it's hex equivalent
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Select Case strBinary
Case "0000"
BinaryToHex = "0"
Case "0001"
BinaryToHex = "1"
Case "0010"
BinaryToHex = "2"
Case "0011"
BinaryToHex = "3"
Case "0100"
BinaryToHex = "4"
Case "0101"
BinaryToHex = "5"
Case "0110"
BinaryToHex = "6"
Case "0111"
BinaryToHex = "7"
Case "1000"
BinaryToHex = "8"
Case "1001"
BinaryToHex = "9"
Case "1010"
BinaryToHex = "A"
Case "1011"
BinaryToHex = "B"
Case "1100"
BinaryToHex = "C"
Case "1101"
BinaryToHex = "D"
Case "1110"
BinaryToHex = "E"
Case "1111"
BinaryToHex = "F"
Case Else
BinaryToHex = "Z"
End Select
End Function
Function WordToBinary(strWord)
' Function Converts a 8 digit hex value into it's 32 bit binary equivalent
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header kept intact
'
Dim strTemp, strBinary
Dim intPos
For intPos = 1 To Len(strWord)
strTemp = Mid(strWord, cint(intPos), 1)
strBinary = strBinary & IntToBinary(Asc(strTemp))
Next
WordToBinary = strBinary
End Function
Function HexToInt(strHex)
' Function Converts a hex word to its base 10(decimal) equivalent
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim intNew, intPos, intLen
intNew = 0
intLen = CDbl(len(strHex)) - 1
For intPos = CDbl(intLen) to 0 step -1
Select Case Mid(strHex, CDbl(intPos) + 1, 1)
Case "0"
intNew = CDbl(intNew) + (0 * 16^CDbl(intLen - intPos))
Case "1"
intNew = CDbl(intNew) + (1 * 16^CDbl(intLen - intPos))
Case "2"
intNew = CDbl(intNew) + (2 * 16^CDbl(intLen - intPos))
Case "3"
intNew = CDbl(intNew) + (3 * 16^CDbl(intLen - intPos))
Case "4"
intNew = CDbl(intNew) + (4 * 16^CDbl(intLen - intPos))
Case "5"
intNew = CDbl(intNew) + (5 * 16^CDbl(intLen - intPos))
Case "6"
intNew = CDbl(intNew) + (6 * 16^CDbl(intLen - intPos))
Case "7"
intNew = CDbl(intNew) + (7 * 16^CDbl(intLen - intPos))
Case "8"
intNew = CDbl(intNew) + (8 * 16^CDbl(intLen - intPos))
Case "9"
intNew = CDbl(intNew) + (9 * 16^CDbl(intLen - intPos))
Case "A"
intNew = CDbl(intNew) + (10 * 16^CDbl(intLen - intPos))
Case "B"
intNew = CDbl(intNew) + (11 * 16^CDbl(intLen - intPos))
Case "C"
intNew = CDbl(intNew) + (12 * 16^CDbl(intLen - intPos))
Case "D"
intNew = CDbl(intNew) + (13 * 16^CDbl(intLen - intPos))
Case "E"
intNew = CDbl(intNew) + (14 * 16^CDbl(intLen - intPos))
Case "F"
intNew = CDbl(intNew) + (15 * 16^CDbl(intLen - intPos))
End Select
Next
HexToInt = CDbl(intNew)
End Function
Function IntToBinary(intNum)
' Function Converts an integer number to it's binary equivalent
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim strBinary, strTemp
Dim intNew, intTemp
Dim dblNew
intNew = intNum
Do While intNew > 1
dblNew = CDbl(intNew) / 2
intNew = Round(CDbl(dblNew) - 0.1, 0)
If CDbl(dblNew) = CDbl(intNew) Then
strBinary = "0" & strBinary
Else
strBinary = "1" & strBinary
End If
Loop
strBinary = intNew & strBinary
intTemp = Len(strBinary) mod 8
For intNew = intTemp To 7
strBinary = "0" & strBinary
Next
IntToBinary = strBinary
End Function
Function PadBinary(strBinary)
' Function adds 0's to a binary string until it reaches 448 bits.
' The lenghth of the original string is incoded into the last 16 bits.
' The end result is a binary string 512 bits long
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim intPos, intLen
Dim strTemp
intLen = Len(strBinary)
strBinary = strBinary & "1"
For intPos = Len(strBinary) To 447
strBinary = strBinary & "0"
Next
strTemp = IntToBinary(intLen)
For intPos = Len(strTemp) To 63
strTemp = "0" & strTemp
Next
strBinary = strBinary & strTemp
PadBinary = strBinary
End Function
Function BlockToHex(strBinary)
' Function Converts a 32 bit binary string into it's 8 digit hex equivalent
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim intPos
Dim strHex
For intPos = 1 To Len(strBinary) Step 4
strHex = strHex & BinaryToHex(Mid(strBinary, intPos, 4))
Next
BlockToHex = strHex
End Function
Function DigestHex(strHex, strH0, strH1, strH2, strH3, strH4)
' Main encoding function. Takes a 128 digit/512 bit hex value and one way encrypts it into
' a 40 digit/160 bit hex value.
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim strWords(79), adoConst(4), strTemp, strTemp1, strTemp2, strTemp3, strTemp4
Dim intPos
Dim strH(4), strA(4), strK(3)
'Constant hex words are used for encryption, these can be any valid 8 digit hex value
strK(0) = "5A827999"
strK(1) = "6ED9EBA1"
strK(2) = "8F1BBCDC"
strK(3) = "CA62C1D6"
'Hex words are used in the encryption process, these can be any valid 8 digit hex value
strH(0) = strH0
strH(1) = strH1
strH(2) = strH2
strH(3) = strH3
strH(4) = strH4
'divide the Hex block into 16 hex words
For intPos = 0 To (len(strHex) / 8) - 1
strWords(cint(intPos)) = Mid(strHex, (cint(intPos)*8) + 1, 8)
Next
'encode the Hex words using the constants above
'innitialize 80 hex word positions
For intPos = 16 To 79
strTemp = strWords(cint(intPos) - 3)
strTemp1 = HexBlockToBinary(strTemp)
strTemp = strWords(cint(intPos) - 8)
strTemp2 = HexBlockToBinary(strTemp)
strTemp = strWords(cint(intPos) - 14)
strTemp3 = HexBlockToBinary(strTemp)
strTemp = strWords(cint(intPos) - 16)
strTemp4 = HexBlockToBinary(strTemp)
strTemp = BinaryXOR(strTemp1, strTemp2)
strTemp = BinaryXOR(strTemp, strTemp3)
strTemp = BinaryXOR(strTemp, strTemp4)
strWords(cint(intPos)) = BlockToHex(BinaryShift(strTemp, 1))
Next
'initialize the changing word variables with the initial word variables
strA(0) = strH(0)
strA(1) = strH(1)
strA(2) = strH(2)
strA(3) = strH(3)
strA(4) = strH(4)
'Main encryption loop on all 80 hex word positions
For intPos = 0 To 79
strTemp = BinaryShift(HexBlockToBinary(strA(0)), 5)
strTemp1 = HexBlockToBinary(strA(3))
strTemp2 = HexBlockToBinary(strWords(cint(intPos)))
Select Case intPos
Case 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19
strTemp3 = HexBlockToBinary(strK(0))
strTemp4 = BinaryOR(BinaryAND(HexBlockToBinary(strA(1)), _
HexBlockToBinary(strA(2))), BinaryAND(BinaryNOT(HexBlockToBinary(strA(1))), _
HexBlockToBinary(strA(3))))
Case 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39
strTemp3 = HexBlockToBinary(strK(1))
strTemp4 = BinaryXOR(BinaryXOR(HexBlockToBinary(strA(1)), _
HexBlockToBinary(strA(2))), HexBlockToBinary(strA(3)))
Case 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59
strTemp3 = HexBlockToBinary(strK(2))
strTemp4 = BinaryOR(BinaryOR(BinaryAND(HexBlockToBinary(strA(1)), _
HexBlockToBinary(strA(2))), BinaryAND(HexBlockToBinary(strA(1)), _
HexBlockToBinary(strA(3)))), BinaryAND(HexBlockToBinary(strA(2)), _
HexBlockToBinary(strA(3))))
Case 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79
strTemp3 = HexBlockToBinary(strK(3))
strTemp4 = BinaryXOR(BinaryXOR(HexBlockToBinary(strA(1)), _
HexBlockToBinary(strA(2))), HexBlockToBinary(strA(3)))
End Select
strTemp = BlockToHex(strTemp)
strTemp1 = BlockToHex(strTemp1)
strTemp2 = BlockToHex(strTemp2)
strTemp3 = BlockToHex(strTemp3)
strTemp4 = BlockToHex(strTemp4)
strTemp = HexAdd(strTemp, strTemp1)
strTemp = HexAdd(strTemp, strTemp2)
strTemp = HexAdd(strTemp, strTemp3)
strTemp = HexAdd(strTemp, strTemp4)
strA(4) = strA(3)
strA(3) = strA(2)
strA(2) = BlockToHex(BinaryShift(HexBlockToBinary(strA(1)), 30))
strA(1) = strA(0)
strA(0) = strTemp
Next
'Concatenate the final Hex Digest
DigestHex = strA(0) & strA(1) & strA(2) & strA(3) & strA(4)
End Function
Function HexAdd(strHex1, strHex2)
' Function adds to 8 digit/32 bit hex values together Mod 2^32
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim intCalc
Dim strNew
intCalc = 0
intCalc = CDbl(CDbl(HexToInt(strHex1)) + CDbl(HexToInt(strHex2)))
Do While CDbl(intCalc) > 2^32
intCalc = CDbl(intCalc) - 2^32
Loop
strNew = IntToBinary(CDbl(intCalc))
Do While Len(strNew) < 32
strNew = "0" & strNew
Loop
strNew = BlockToHex(strNew)
if InStr(strNew, "00") = 1 and len(strNew) = 10 then
strNew = right(strNew, 8)
end if
HexAdd = strNew
End Function
Function getHexDec(strHex)
' Function Converts a single hex value into it's decimal equivalent
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Select Case strHex
Case "0"
getHexDec = 0
Case "1"
getHexDec = 1
Case "2"
getHexDec = 2
Case "3"
getHexDec = 3
Case "4"
getHexDec = 4
Case "5"
getHexDec = 5
Case "6"
getHexDec = 6
Case "7"
getHexDec = 7
Case "8"
getHexDec = 8
Case "9"
getHexDec = 9
Case "A"
getHexDec = 10
Case "B"
getHexDec = 11
Case "C"
getHexDec = 12
Case "D"
getHexDec = 13
Case "E"
getHexDec = 14
Case "F"
getHexDec = 15
Case Else
getHexDec = -1
End Select
End Function
Function getDecHex(strHex)
' Function Converts a single decimal value(0 - 15) into it's hex equivalent
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Select Case CInt(strHex)
Case 0
getDecHex = "0"
Case 1
getDecHex = "1"
Case 2
getDecHex = "2"
Case 3
getDecHex = "3"
Case 4
getDecHex = "4"
Case 5
getDecHex = "5"
Case 6
getDecHex = "6"
Case 7
getDecHex = "7"
Case 8
getDecHex = "8"
Case 9
getDecHex = "9"
Case 10
getDecHex = "A"
Case 11
getDecHex = "B"
Case 12
getDecHex = "C"
Case 13
getDecHex = "D"
Case 14
getDecHex = "E"
Case 15
getDecHex = "F"
Case Else
getDecHex = "Z"
End Select
End Function
Function BinaryShift(strBinary, intPos)
' Function circular left shifts a binary value n places
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
BinaryShift = Right(strBinary, Len(strBinary) - cint(intPos)) & _
Left(strBinary, cint(intPos))
End Function
Function BinaryXOR(strBin1, strBin2)
' Function performs an exclusive or function on each position of two binary values
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim strBinaryFinal
Dim intPos
For intPos = 1 To Len(strBin1)
Select Case Mid(strBin1, cint(intPos), 1)
Case Mid(strBin2, cint(intPos), 1)
strBinaryFinal = strBinaryFinal & "0"
Case Else
strBinaryFinal = strBinaryFinal & "1"
End Select
Next
BinaryXOR = strBinaryFinal
End Function
Function BinaryOR(strBin1, strBin2)
' Function performs an inclusive or function on each position of two binary values
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim strBinaryFinal
Dim intPos
For intPos = 1 To Len(strBin1)
If Mid(strBin1, cint(intPos), 1) = "1" Or Mid(strBin2, cint(intPos), 1) = "1" Then
strBinaryFinal = strBinaryFinal & "1"
Else
strBinaryFinal = strBinaryFinal & "0"
End If
Next
BinaryOR = strBinaryFinal
End Function
Function BinaryAND(strBin1, strBin2)
' Function performs an AND function on each position of two binary values
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim strBinaryFinal
Dim intPos
For intPos = 1 To Len(strBin1)
If Mid(strBin1, cint(intPos), 1) = "1" And Mid(strBin2, cint(intPos), 1) = "1" Then
strBinaryFinal = strBinaryFinal & "1"
Else
strBinaryFinal = strBinaryFinal & "0"
End If
Next
BinaryAND = strBinaryFinal
End Function
Function BinaryNOT(strBinary)
' Function makes each position of a binary value from 1 to 0 and 0 to 1
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim strBinaryFinal
Dim intPos
For intPos = 1 To Len(strBinary)
If Mid(strBinary, cint(intPos), 1) = "1" Then
strBinaryFinal = strBinaryFinal & "0"
Else
strBinaryFinal = strBinaryFinal & "1"
End If
Next
BinaryNOT = strBinaryFinal
End Function
Function HexBlockToBinary(strHex)
' Function Converts a 8 digit/32 bit hex value to its 32 bit binary equivalent
'
' Written By: Mark Jager
' Written Date: 8/10/2000
'
' Free to distribute as long as code is not modified, and header is kept intact
'
Dim intPos
Dim strTemp
For intPos = 1 To Len(strHex)
strTemp = strTemp & HexToBinary(Mid(strHex, cint(intPos), 1))
Next
HexBlockToBinary = strTemp
End Function
msgbox HashEncode("1") 转载 :http://hi.baidu.com/myvbscript/blog/item/0d30c100a2807c16738b6571.html
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