中国DOS联盟

If the content in 1.txt is the same as that in 2.txt, replace it with blank.

1.txt
c:\windows
c:\windows\12.txt

2.txt
c:\windows
c:\windows\21.txt
c:\windows\123.txt
c:\my doc

The output is 3.txt
c:\windows\123.txt
c:\my doc

Last edited by namejm on 2007-2-5 at 10:24 AM ]

@echo off

:: 比较A文件夹和B文件夹下文件名的异同(A和B文件夹下均无子目录)

:: 如果有不同，A文件夹中不同的写入a.txt，B文件夹中不同的写入b.txt

:: 相同部分的文件名写入c.txt

cd.>a.txt

cd.>b.txt

cd.>c.txt

dir /a-d /b "A文件夹的路径">list_a.txt

dir /a-d /b "B文件夹的路径">list_b.txt

for /f "delims=" %%i in (list_a.txt) do (

    find "%%i" list_b.txt>nul 2>nul && echo %%i>>c.txt || echo %%i>>a.txt

)

for /f "delims=" %%i in (list_b.txt) do (

    find "%%i" list_a.txt>nul 2>nul || echo %%i>>b.txt

)

del /q list_a.txt>nul 2>nul

del /q list_b.txt>nul 2>nul

start a.txt

start b.txt

start c.txt

There was a similar discussion post before, but I can't find it at once. So I simply post the previously sent complete code for your reference:

@echo off

:: Compare the differences in file names between folder A and folder B (there are no sub - directories under both folder A and folder B)

:: If there are differences, write the different ones in folder A to a.txt and the different ones in folder B to b.txt, and write the same part of file names to c.txt

cd.>a.txt

cd.>b.txt

cd.>c.txt

dir /a-d /b "Path of folder A">list_a.txt

dir /a-d /b "Path of folder B">list_b.txt

for /f "delims=" %%i in (list_a.txt) do (

    find "%%i" list_b.txt>nul 2>nul && echo %%i>>c.txt || echo %%i>>a.txt

)

for /f "delims=" %%i in (list_b.txt) do (

    find "%%i" list_a.txt>nul 2>nul || echo %%i>>b.txt

)

del /q list_a.txt>nul 2>nul

del /q list_b.txt>nul 2>nul

start a.txt

start b.txt

start c.txt

@echo off

cd.>3.txt

for /f "tokens=*" %%i in (2.txt) do (

    find "%%i" 1.txt || >>3.txt echo %%i

)

start 3.txt

Considering that you are a newbie and it's hard for you to understand the complete code in building 2, here is a code customized for you:

@echo off

cd.>3.txt

for /f "tokens=*" %%i in (2.txt) do (

    find "%%i" 1.txt || >>3.txt echo %%i

)

start 3.txt

c:\windows\21.txt

c:\windows\123.txt

c:\my doc

c:\windows\123.txt

c:\my doc

Today I had nothing to do, so I pulled out the code from the third floor to play with. The result surprised me a lot: the content of 3.txt is

c:\windows\21.txt

c:\windows\123.txt

c:\my doc

instead of what the original poster said

c:\windows\123.txt

c:\my doc

.

Oh my god, I'm having another setback. Alas, the original posters are really hard to deal with now.

Thanks everyone, but I tried this method and some can't be replaced. For example, the last name is LNK,

for /f "delims==" %%i in (1.txt) do findstr /l /i /x "%%i" "2.txt" ||if %errorlevel% == 0 echo %%i >>3.txt

>>3.txt echo %%i

The one above can also be written in reverse, why?

So far, no one has been able to solve it.

Originally posted by hhh246 at 2006-9-4 13:09:
There is still no one who can solve it yet,

　　Really?

　　Have you tested the above code by yourself? Can you ensure that there are no errors in your statement in the top post?

for /f "delims==" %%i in (1.log) do (
find /i "%%i" "2.log" || echo %%i>>b.txt
)

It works, but it's quite slow. Can anyone write a multi-threaded one?

Originally posted by hhh246 at 2006-9-8 08:52:
for /f "delims==" %%i in (1.log) do (
find /i "%%i" "2.log" || echo %%i>>b.txt
)

It works, but the speed is quite slow. Can anyone write a multithreaded one?

　　Is the speed slow? Unless you are dealing with tens of thousands of lines of text.

　　Multithreaded? Hehe, CMD is in single-task mode, so it's impossible to implement multithreading.

Last edited by namejm on 2006-9-8 at 11:26 ]

findstr /v /x /g:1.txt 2.txt

findstr /v /x /g:1.txt 2.txt

The code of moderator 3742668 is extremely concise and efficient, PF.